Section 2How your score is calculated.
The LensWideOpen Score isn’t a vote count. It’s a strength estimate that asks: given who you beat and who beat you, how strong must you be? Two entries with the same win-loss record can finish with different ranks if the quality of their opponents differs.
The intuition
Imagine two photographers, P and Q, who both go 5 wins, 5 losses in a contest:
- P’s wins were against entries that mostly lost their other matchups — weak opponents.
- Q’s wins were against entries that mostly won their other matchups — strong opponents.
A naive “count the wins” ranking puts them tied. The LensWideOpen Score puts Q ahead, because beating a strong photograph is more informative than beating a weak one.
A worked example
Four entries — A, B, C, D — each pair voted exactly 10 times. After the contest closes, the matchup table looks like this:
| Matchup | Winner | Score |
|---|
| A vs B | A | 7 – 3 |
| A vs C | A | 6 – 4 |
| A vs D | A | 8 – 2 |
| B vs C | B | 6 – 4 |
| B vs D | B | 7 – 3 |
| C vs D | C | 5 – 5 |
Tally by raw wins (each row contributes the winner’s margin):
| Entry | Wins | Losses | Win rate |
|---|
| A | 21 | 9 | 70% |
| B | 16 | 14 | 53% |
| C | 13 | 17 | 43% |
| D | 10 | 20 | 33% |
In this case the LensWideOpen Score and the win-rate ranking agree — A > B > C > D — because the strength order is consistent across every matchup. The LensWideOpen Score adds value when the win-rate order doesn’t agree (e.g., a photo with fewer wins beat opponents who themselves dominated their other matchups). The method handles those cases by iteratively weighting each win by the current estimate of the opponent’s strength until the scores converge.
The math behind it
The LensWideOpen Score is computed with the Bradley-Terry method, a well-established pairwise ranking model first published in 1952 and used in chess, sports analytics, and machine-learning evaluation. Each entry receives a strength score s. The probability that entry i beats entry j is si / (si + sj). The algorithm solves for the set of s values that best fits the matchup results we observed. Source: Bradley–Terry model.